# C Program to check if the given number is an Armstrong Number

|In this C Programming example, we will implement the program to check whether the given number is an *Armstrong Number* *or not* by using the user’s input and print it on screen.

Table of Contents

## 1. What are **Armstrong Number**s?

A positive integer is called an Armstrong number if the *sum of the cubes of the digits is equal to the number itself*. For example, 153 is an Armstrong number because the Armstrong number is a number that is equal to the sum of cubes of its digits.

For example0, 1, 153, 370, 371 and 407 are Armstrong numbers.

Let’s have a look at 153 and understand why it is considered an Armstrong number.

153 = (1*1*1) + (5*5*5) + (3*3*3) where: (1*1*1) = 1 (5*5*5) = 125 (3*3*3) = 27 So: 1 + 125 + 27 = 153

Now, let us continue with this article on **Armstrong Number** **in C** and take a look at how to implement a program for the same.

Here are some helpful topics to understand this program better.

## 2. C Program to find the **Armstrong Number**

Let’s discuss the execution(kind of pseudocode) for the program to check whether an integer entered by the user is an Armstrong number or not in C.

- Initially, take the integer as input and assign it to the variable
`number`

and pass it to`int checkForArmstrong(int number)`

. - From right to left, fetch a single digit(
`remainder`

) of the number and find its cube - Then add all the cube values together.
- Check whether the sum of the cube of digits is equal to the number itself.
- Finally, print the relevant output to the console.

Let us implement this concept in C Program to find the armstrong number.

#include <stdio.h> int checkForArmstrong(int number) { int sum = 0, remainder; while (number != 0) { remainder = number % 10; sum = sum + (remainder * remainder * remainder); number = number / 10; } return sum; } int main() { int number, sum = 0; printf("\nEnter a number:"); scanf("%d", &number); sum = checkForArmstrong(number); // Condition is evaluated for a number to be an armstrong number. if (number == sum) { printf("\n%d is an Armstrong Number", number); } else { printf("\n%d is not an Armstrong Number", number); } return (0); }

Enter a number:407 407 is an Armstrong Number

## 3. Conclusion

In this C Programming example, we have discussed how to check whether the given number is an *Armstrong Number* or not by using the user’s input and finally, print the result to the console.

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